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If `sinx+sin^2x=1` then the value of `cos^2x+cos^4x+cot^4x-cot^2x` is
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If `sinx+sin^2x=1` then the value of `cos^2x+cos^4x+cot^4x-cot^2x` is
Ex 3.4, 6 - Find general solution of cos 3x + cos x - cos 2x = 0
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Solve :- rn cosx + sinx = cos2x + sin2x - Maths - Trigonometric
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